Data Interpretation (D.I.) MCQs for NTA UGC NET Paper 1

Here we are going to discuss some important topics, Data Interpretation D.I. MCQs and tricks of Data Interpretation (D.I.) for NTA UGC NET Paper 1 MCQs. Herewith some practical solutions, you can able to learn to solve the Data Interpretation D.I. MCQs Questions MCQs with easy tricks.

Data Interpretation (D.I.) MCQs for NTA UGC NET Paper 1

QUESTIONS:

(1-5) Study the given table carefully to answer the following questions.

Field Name	Shape	Side (in m)	Base (in m)	Height (in m)	Radius (in m)	Cost of flooring (in Rs. per sq. metre)	Cost of fencing (in Rs. per m)
A	Triangle		16	12		50	20
B	Rectangle	10 × 20				30	15
C	Square	15				40	18
D	Parallelogram		20	12		60	25
E	Circle				10	45	22

Q1. What is the cost of flooring of A?

a) Rs.4000 b) Rs.4600 c) Rs.4800
d) Rs.5000 e) Rs.4400

Q2.What is the difference between the cost of fencing of C and that of B?

a) Rs.180 b) Rs.120 c) Rs.240
d) Rs.360 e) Rs.480

Q3. What is the ratio of the cost of flooring to that of fencing of field D?

a) 4 : 1 b) 6 : 1 c) 8 : 1
d) 9 : 1 e) 5 : 1

Q4. The cost of fencing of field E is approximately what percent of the cost of flooring of field C?

a) 10.5% b) 19.46% c) 18.71%
d) 15.36% e) 13.82%

Q5. The cost of fencing of field C is what percent of the cost of fencing of field D?

a) 87.54% b) 67.5% c) 72.13%
d) 54.36% e) 46.5%

ANSWERS:

Option C

A is a triangle

So, area of A = 1/2 × 16 × 12 = 96 sqm

So, cost of flooring of A = 96 × 50 = Rs.4800

Option A

Perimeter of B = 2 (10 + 20) = 60 m

So, cost of fencing of B = 60 × 15 = 900

Perimeter of C = 4 × 15 = 60 m

So, cost of fencing of C = 60 × 18 = Rs.1080

So, required difference = 1080 – 900 = Rs.180

Option D

Area of D = Base × Height

= 20 × 12 = 240m²

So, cost of flooring of D= 240 × 60 = Rs.14400

Perimeter of D = 2 (20 + 12) = 64 m

So, cost of fencing of D = 64 × 25 = Rs.1600

So, required ratio = 14400 : 1600 = 9 : 1

Option D

Perimeter of E = 2πr = 2 × 22 / 7 × 10 = 440 / 7 m

Cost of fencing of E = 440 / 7 × 22 = Rs.1382.85

Area of C = (15)²= 225m²

So, cost of flooring of C = 225 × 40 = Rs.9000

So, required % = 1382.85 × 100 / 9000

= 15.36% of flooring cost of C.

Option B

Fencing cost of C = Rs.1080

Fencing cost of D = Rs.1600

Required % = 1080 / 1600 × 100 = 67.5%

PIE-CHART D.I.

QUESTIONS:

Directions (1-5): Study the following the pie-chart and table carefully to answer the questions given below:

The following pie-chart shows the distribution of the monthly family budget of a person.

The following table shows the further distribution (in percent) of the above-mentioned items among the five family members i.e P (the person himself), W (his wife), Rahul (son), Rohit (son), and Preeti (his daughter). His monthly family budget is Rs. 1,20,000

	Education	Food	Entertainment	Travelling	Other expenses
P	10	30	10	40	20
W	15	25	30	10	25
Rahul	40	20	20	25	20
Rohit	25	15	25	10	10
Preeti	10	10	15	15	25

1. What is the average expenses of P?
1. Rs. 5620
2. Other than the given options
3. Rs. 5640
4. Rs. 5460
5. Rs. 5480
2. What is the approximate percentage increase in the amount Which Rahul enjoys for entertainment as compared to Preeti for the same?
1. 33%
2. 31%
3. Other than the given options
4. 37%
5. 35%
3. The average expenses of Rohit is approximately what percent of the average expenses of W (Wife)?
1. 76.4%
2. 81.5%
3. 79.5%
4. 83.5%
5. Other than the given options

4. Find the difference (in the percentage of the budget) between the average expenses of Education and the average expenses on Entertainment of the couple?
1. 1.3%
2. 0.9%
3. 2%
4. Other than the given options
5. 2.5%
5. The total amount spent by Rahul on Travelling and Food is approximately what percent of the total amount spent by Preeti on Education and Food?
1. Other than the given options
2. 168%
3. 171%
4. 175%
5. 174%